f(-x)=-f(x)(px²+2)/(-3x+q)=-(px²+2)/(3x+q)这是恒等式而px²+2不是恒等于0所以可以约分1/(-3x+q)=-1/(3x+q)-3x+q=-3x-qq=0f(x)=(px²+2)/(3x)f(2)=(4p+2)/6=5/3p=2f(x)=(2x²+2)/(3x)令x1...