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log以4为底3×log以9为底2+log以2为底^4√64 求值
log以9为底32×log以64为底27+log以9为底2×log以4为底√27 求值
人气:235 ℃ 时间:2020-08-18 08:52:23
解答
log以9为底32×log以64为底27+log以9为底2×log以4为底√27
=lg32/lg9×lg27/lg64+lg2/lg27×lg√27/lg4
=5/2lg2/lg3×3/6lg3/lg2+1/3lg2/lg3×3/4lg3/lg2
=5/2x3/6+1/3x3/4
=5/4+1/4
=1.5lg√27/lg4怎么算出3/4lg3/lg2lg√27=1/2lg27=3/2lg3lg4=2lg2lg√27/lg4=3/2lg3/(2lg2)=3/4lg3/lg2
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