f(x)＝(√3sinwx＋coswx)coswx－1/2＝√3sinwxcoswx＋cos²wx－1/2＝√3/2(2sinwxcoswx)＋1/2(2cos²wx－1)＝√3/2sin(2wx)＋1/2cos(2wx0＝sin(2wx＋π/6)∴2π/(2w)＝4π ∴w＝1/2∴f(x)＝sin(x＋π/6)∴当...w=1/2? 我算的是1/4 啊∴2π/(2w)＝4π∴w＝1/4∴f(x)＝sin(x/2＋π/6)∴当x/2＋π/6∈[2kπ－π/2,2kπ＋π/2]即x∈[4kπ－4π/3,4kπ＋2π/3]时，f(x)单调递增当x/2＋π/6∈[2kπ＋π/2,2kπ＋3π/2]即x∈[4kπ＋2π/3,2kπ＋8π/3]时，f(x)单调递减