2不整除m,设m=2a+13不整除m,设m=3b+1或3b-1m^2+23=(2a+1)^2+23=4a^2+4a+1+24=4a(a+1)+24a和a+1为相邻的自然数,一奇一偶所以a(a+1)能被2整除那么4a(a+1)就能被8整除4a(a+1）+24能被8整除m^2+23=(3b+1)^2+23=9b^2+6b+1...