设数列{an}的前n项和为Sn,已知S1=1,Sn+1/Sn=n+c/n (c为常数,c≠1,n∈N*)且a1,a2,a3成等差数列
（3）若数列{bn}是首项为1,公比为c的等比数列,记An=a1b1=a1b2+...+anbn,Bn=a1b1-a2b2+...+（-1）^n-1anbn,n属于正整数.证明An+3B2n<=-4