解析f(x)=1/2(1-cos2x)+√3sinx×cosx+1/2,=1/2-1/2cos2x+√3/2sin2x+1/2=sin(2x-π/6)+1所以函数的最小正周期T=2π/w=π当sin(2x-π/6)=1时取得最大值22x-π/6=π/2+2kπx=kπ+π/3当sin(2x-π/6)=-1取得最小值0此...