﹙㏒（3）2+㏒（9）2﹚*（㏒﹙4﹚3＋㏒﹙8﹚3）
=[log3(2)+(1/2)log3(2)]*[(1/2)log2(3)+(1/3)log2(3)]
=(3/2)log3(2)*(5/6)log2(3)
=(5/4)log3(2)*log2(3)
=5/4
注：loga(b)与logb(a)互为倒数