∵x2-3＞ax-a对一切3≤x≤4恒成立∴a＜x2− 3x−1在x∈[3，4]恒成立令g(x)＝x2−3x−1，x∈[3，4]即a＜g（x）min而g(x)＝x2−3x−1=(x−1)2+2(x−1)−2x−1=(x−1)−2x−1+ 2在x∈[3，4]单调递增故g（x）...