圆心为C(b,-a),半径r = 1圆心与直线ax + by - 1 = 0的距离为d = |ab -ab - 1|/√(a²+b²) = 1/√(a²+b²) < r = 1a²+b²> 1PC²= (a - b)² + (b + a)² = 2(a² + b
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