设方程为y=kx+b,有k+b=2,则有方程为kx-y+(2-k)=0d=|2k-3+(2-k)|/(k^2+1)^1/2=|4k+5+(2-k)|/(k^2+1)^1/2有|k-1|=|3k+7|,(k-1)^2=(3k+7)^2解得:k1=-4,k2=-3/2k1=-4时,方程为y=-4x+6k2=-3/2时,方程为y=-3/2x+7/2...