已知有理数x,y,z满足(x-4)的平方+3|x+y+z|=0,则(5x+3y-3z)的2008次方的末位数字是多少?
(x-4)^2+3|x+y-z|=0
x-4=0
x=4
x+y-z=0
y-z=-x=-4
,则(5x+3y-3z)^2008
=[5*4+3*(-4)]^2008
=8^2008
=(8^2)^1004
=64^1004
=(64^2)^502
=4096^502
=.6
6的任何次方等于6
则(5x+3y-3z)的2008次方的末位数字是6