g(x)=f(x-1)
g(-x)=f(-x-1)=-f(x+1)
g(x)=g(-x)
=>-f(x-1)=f(x+1)
f(2010)=-f(2008)=f(2006)=...=-f(4)
f(4)=g(3)=2010
=>f(2010)=-2010