已知关于x、y的方程组
的解都是正数,求a的取值范围.
人气:257 ℃ 时间:2020-06-13 16:37:07
解答
x+y=a①5x+3y=15②,①×3得,3x+3y=3a③,②-③得,2x=15-3a,解得x=15−3a2,把x=15−3a2代入①得,y=a-x=a-15−3a2=5a−152,∴原方程组的解是x=15−3a2y=5a−152,∵方程组的解都是正数,∴15−3a2>0①5a−...
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