y=1/2cos²x+根号3/2sinxcosx＋1=1/2cos²x＋1+根号3/2sinxcosx=1/2(1/2cos2x+根号3/2sin2x)=1/2[sin(2x+π/6)]∴当2x+π/6=2kπ+π/2即x=kπ+π/6y取得最大值1/2∴｛x│x=kπ+π/6（k∈N*）｝y有最大值1/2...