x^2+p(x+1)+1=0x^2+px+p+1=0因为tanA,tanB是方程x^2＋p(x＋1）＋1＝0的两个实根所以tanA+tanB=-p,tanA*tanB=p+1所以tan(A+B)=(tanA+tanB)/(1-tanA*tanB)=-p/(1-p-1)=1故A+B=π/4所以C=π-π/4=3π/4...