已知y=f(x)是二次函数,且满足f(0)=1,f(x+1)-f(x)=2X,求f(x)
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人气:478 ℃ 时间:2020-08-01 09:38:05
解答
set f(x)=ax^2+bx+c(a is not equal to 0)since f(0)=1, so c=1f(x+1)-f(x)=2x,then a(x+1)^2+b(x+1)-ax^2-bx=2xso 2ax+a+b=2xthat is equal to saya=1,b=-1so f(x)=x^2-x+1
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