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数学
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已知tanα=2,求2sin² α - 3sinαcosα的值
人气:137 ℃ 时间:2019-11-01 22:53:41
解答
2sin² α - 3sinαcosα
=(2sin² α - 3sinαcosα)/(sin² α + cos²α)
=(2tan² α - 3tanα)/(tan² α + 1)
=(8-6)/(4+1)
=2/5
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