(2+1)(2^2+1)(2^3+1)(2^4+1))(2^5+1)(2^6+1)(2^7+1)(2^8+1)（2^9+1）（2^_数学解答

(2+1)(2^2+1)(2^3+1)(2^4+1))(2^5+1)(2^6+1)(2^7+1)(2^8+1)（2^9+1）（2^16+1）（2^32+1）详细过程.3Q…

人气：220 ℃　时间：2020-04-20 07:42:27

解答

原式=(2+1)(2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2-1)=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2-1)=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2-1)=(2^8-1)(2^8+1)(2^16+1)(2^32+1)/(2-1)=(2^16-1)(2^16+1)(2^32+1)/(2-1)=(2^32-1)(2^32+1)/(2-1)=(2^64-1)/(2-1)=2^64-1