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1/2+1/(2+4)+1/(2+4+6)+...1/(2+4+6+...2n),求和
人气:445 ℃ 时间:2020-05-15 03:17:32
解答
1/2+1/(2+4)+1/(2+4+6)+...1/(2+4+6+...2n)
=1/(1×2)+1/(2×3)+1/(3×4)+.+1/[n(n+1)]
=1-1/2+1/2-1/3+1/3-1/4+.+1/n-1/(n+1)
=1-1/(n+1)
=n/(n+1)
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