设an公差不为0的等差数列.(1)前n项和为Sn,Sn=110,a1.a2.a4为等比数列.求an通项公式.
人气:275 ℃ 时间:2019-10-17 07:22:44
解答
设公差da2 = a1 + da4 = a1 +3da10 = a1 + 9dS10 = (a1 +a10)*10/2 = 5(2a1 + 9d) = 1102a1 + 9d = 22a1.a2.a4为等比数列a2 * a2 = a1 * a4(a1 + d)^2 = a1(a1 + 3d)d^2 - a1*d = 0d = a1 ( d = 0 舍去)2*a1 + 9*a1 ...
推荐
- 设an是一个公差为d(d不等与0)的等差数列,它的前n项和Sn=110且a1,a2,a4成等比数列,证明:a1=d
- 设{an}是公差不为0的等差数列额,a1=2,且a1,a3,a6成等比数列,则{an}的前n项和Sn=( )
- 设{an}是一个公差不为0的等差数列,它的前十项和S10为110,且a1,a2,a4成等比数列.
- 设an是公差不为0的等差数列,a1=2且a1,a3,a6成等比数列,则an的前n项和Sn=
- (2011•锦州三模)已知公差不为0的等差数列{an}满足a1,a3,a4成等比关系,Sn为{an}的前n项和,则S3−S2S5−S3的值为( ) A.2 B.3 C.15 D.不存在
- 设全集I=﹛2,3,a²+2a-3﹜,A=﹛2,/a+1/﹜,A的补集=﹛5﹜,M=﹛x/x=以2为底/a/的对数﹜,
- 有规则几何形状的物体一定是晶体对吗?
- You will learn __if you read __books
猜你喜欢