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已知sina=5/13,a∈(π/2,π),则sin2a=?cos2a=?tan2a=?sina/2=、cosa/2=?tana/2=?
人气:205 ℃ 时间:2020-04-16 14:19:04
解答
sina=5/13,a∈(π/2,π),cosa=-根号[1-(sina)^2]=-12/13,sin2a=2sina*cosa=-120/169,cos2a=1-2(sina)^2=119/169,tan2a=sin2a/cos2a=-120/119 a/2∈(π/4,π/2)sina/2=根号[(1-cosa)/2]=5带根号26/26 cosa/2=根号[(1+cosa)/2]=根号26/26,tana/2=5
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