求周长为根号2+1的直角三角形的面积的最大值是?
人气:171 ℃ 时间:2019-08-20 03:22:39
解答
√2+1=a+b+√(a²+b²)≥2√ab+√2ab=√(2ab)(√2+1)
ab≤1/2 当且仅当a=b=√2/2 时取等号
S=1/2*ab≤1/2*1/2=1/4
直角三角形的面积的最大值是1/4
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