已知tanα=-1/2,则(sinα-cosα)²/cos2α=?
人气:490 ℃ 时间:2020-02-04 01:50:44
解答
(sinα-cosα)²/cos2α=(sina²-2sinacosa+cosa²)/(cosa²-sina²)除cosa²=(tana²-2tana+1)/(1-tana²)=(1/4+1+1)/(1-1/4)=(9/4)/(3/4)=3
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