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化简{Cos(1800+α)sin(-α)}除以tan(-α-180o)
人气:434 ℃ 时间:2020-05-10 03:24:15
解答
cos(180°+α)*sin(-α)/tan(-α-180°)
=-cosα*(-sinα)/tan(-α)
=sinα*cosα/(-tanα)
=sinα*cosα*cosα/(-sinα)
=-(cosα)^2
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