过E作EF∥AC交BC于F.∵EF∥AC,∴△ABC∽△EBF,而△ABC是等边三角形,∴△EBF也是等边三角形,∴BE＝BF＝EF、∠EBF＝∠EFB＝60°,∴∠EBD＝∠EFC＝120°.∵△ABC是等边三角形,∴AB＝BC,又BE＝BF,∴AE＝CF.∵DE＝CE,∴∠...