(1-√3i)^2=1-2√3i+3i^2=1-2√3i-3=-2-2√3i=-2(1+√3i)所以(1-√3i)^3=-2(1-√3i)(1+√3i)=-2(1-3i^2)=-8所以(1-√3i)^6=(-8)^2=64(1+i)^2=1+2i+i^2=2i所以(1+i)^8=(2i)^4=16所以(1-√3i)^6/(1+i)^8=64/16=4...