f''(x)存在,y=(x^2)的二阶导数是多少?怎么写,
答案是2f'(x^2)+4x^2f''(x^2)
人气:134 ℃ 时间:2019-08-31 02:03:48
解答
y'=2xf'(x^2)
y''=2f'(x^2)+2xf''(x^2)*(2x)=2f'(x^2)+4x^2f''(x^2)
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