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若三角形ABC为锐角三角形,满足sinA/sinB=cos(A+B)则tanA最大值
人气:319 ℃ 时间:2019-09-06 03:49:20
解答
sinA/sinB=cos(A+B)=cosAcosB-sinAsinB;sinA/cosA=sinB(cosAcosB-sinAsinB)/cosAtanA=sinB(cosB-tanAsinB)tanA=(sinBcosB)/(1+sinB^2)=sin2B/(2+2sinB^2)=sin2B/(3-cos2B)相当于圆x^2+y^2=1上面一个动点与定点(3,0...
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