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数学
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|x-1 | /x的导数怎么求还有极值和拐点
人气:276 ℃ 时间:2020-05-12 06:06:19
解答
x=1,f(x) = |x-1 | / x = 0
x>1,f(x) = |x-1 | / x = 1 - 1/x
f '(x) = 1/x²,f ''(x) = -2/x³
f(x) 单增,是凸函数;
x
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