∫sinxdx/(sinx+cosx)=∫sinx(cosx-sinx)dx/cos2x=∫(-1/2)dcos2x/cos2x + ∫(1/2)(cos2x-1)dx/cos2x=(-1/2)ln|cos2x| -∫(1/4)d2x/cos2x +(1/2)x =(-1/2)ln|cos2x|-(1/8)ln[(1+cos2x)/(1-cos2x)] +(1/2)x +C=(-1/2)...