因为f（x）=3x/(x+3) xn=f(Xn-1)所以xn=f(x(n-1))=3x(n-1)/(x(n-1)+3)于是xn[x(n-1)+3]=3x(n-1)xnx(n-1)+3xn=3x(n-1)上式两边同除以xnx(n-1)得1+3/x(n-1)=3/xn即3/xn-3/x(n-1)=1所以数列{3/xn}是以3/x1为首项,...