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已知sin(5π-θ)+sin(5π/2-θ)=根号7/2
求[sin(π/2+θ)]^2-[cos(3π/2-θ)]^2的值
人气:479 ℃ 时间:2020-05-26 01:59:35
解答
sin(5π-θ)+sin(5π/2-θ)=√7/2
sinθ+cosθ=√7/2,1+sin2θ=7/4,sin2θ=3/4 ,cos2θ=±√7/4
sin(π/2+θ)]^2-[cos(3π/2-θ)]^2=cos^2θ-sin^2θ=cos2θ=±√7/4
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