求dy/dx y=x^(1/n)隐函数微分~答案是不是y'=(1/n)x^(1/n-1)_数学解答

求dy/dx y=x^(1/n)隐函数微分~
答案是不是y'=(1/n)x^(1/n-1)

人气：460 ℃　时间：2019-09-06 02:00:29

解答

y=x^(1/n)
lny=(lnx)/n
d(lny)/dx = 1/(nx)
y'/y = 1/(nx)
y' = y/(nx)
dy/dx = x^(1/n)/(nx)
= (1/n)x^(1/n - 1)
你的结论是对的.