若实数a、b满足(a²-b²)²-(a²-b²)-6=0,则a²-b²的值为
(a²-b²-3)(a²-b²+2)=0;
a²-b²=3或a²-b²=-2;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,