f(x)=2cosx/2(sinx/2+cosx/2)+4=2sinx/2cosx/2+2cos^2 x/2+4=sinx+cosx-1+4=√2(√2/2sinx+√2/2cosx)+3=√2sin(x+π/4)+3所以最小正周期T=2π/1=2π增区间是 2kπ+π/2>=x+π/4>=2kπ-π/22kπ+π/4>=x>=2kπ-3π/4...