解psin(θ+π/4)=√2psinθcosπ/4+pcosθsinπ/4=√2∴1/2y+1/2x=1即x+y-2=0A(2,7π/4)化为直角坐标系x=2×cos7π/4=-2×(√2/2)=√2y=2×sin7π/4=2×(√2/2)=-√2即(√2,-√2)到直线x+y-2=0的距离d=|√2-√2-2|/...