答：
原式
=(x^2-7x+6)(x^2-x-6)+56
=(x-6)(x-1)(x-3)(x+2)+56
=[(x-6)(x+2)][(x-1)(x-3)]+56
=(x^2-4x-12)(x^2-4x+3)+56
=(x^2-4x)^2+(3-12)(x^2-4x)+(3*(-12))+56
=(x^2-4x)^2-9(x^2-4x)+20
=(x^2-4x-4)(x^2-4x-5)
=(x^2-4x-4)(x-5)(x+1)