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[(根2/(1-i)]^2010=?
人气:370 ℃ 时间:2020-07-04 00:04:10
解答
[(根2/(1-i)]²=(1+i)²=2i
[(根2/(1-i)]^4=(2i)²=-4
[(根2/(1-i)]^8=16
[(根2/(1-i)]^2008=16^251
[(根2/(1-i)]^2010=16^251*2i=2^1005i
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