连接OE,BD∵正方形ABC内接于圆O∴O点在BD上且为BD中点∵圆O半径=√2∴BD=2√2∴正方形边长=2【勾投定理】∵E是DC中点∴OF=BC/2=1,EC=ED=1∴BE=√5【勾股定理】∵S△OBE=OE*FC/2=BE*OM/2∴OE*FC=BE*OM即1*1=√5*OM∴O...