f(x)=√3/4*sin2x+1/4*(1+cos2x)+1=√3/4*sin2x+1/4*cos2x)+5/4=(1/2)sin(2x+z)+5/4tanz=(1/4)/(√3/4)=1/√3z=π/6所以f(x)=(1/2)sin(2x+π/6)+5/4所以T=2π/2=πf(x)=1sin(2x+π/6)=-1/22x+π/6=2kπ-π/6,2x+π/6...