过两圆x²+y²-3x=0 与x²+y²+4y-8=0的交点且过(1,1)的圆的方程
人气:115 ℃ 时间:2019-11-05 05:02:52
解答
过两圆x²+y²-3x=0 与x²+y²+4y-8=0的交点
所以是x²+y²-3x+λ(x²+y²+4y-8)=0
过(1,1)
代入
-1-2λ=0
λ=-1/2
所以是x²+y²-6x-4y+8=0
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