> 数学 >
方程sinx+根号3cosx+a=0在(0,π/2)内有相异两根α、β,求α+β
人气:389 ℃ 时间:2020-10-02 05:48:22
解答
2sinx+√3cosx+a=02sin(x+π/3)=-asin(x+π/3)=-a/2x+π/3=2kπ+arcsin(-a)或x+π/3=2kπ+π-arcsin(-a/2)α=2kπ-arcsina/2-π/3 β=2kπ+π+arcsina/2-π/3α+β=4kπ+π/3∵α+β∈(0,π)∴α+β=π/3不...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版