已知平面直角坐标系中,点O为原点,A(-3,-4),B(5,-12),求OA*OB?...._数学解答

已知平面直角坐标系中,点O为原点,A(-3,-4),B(5,-12),求OA*OB?
....

人气：329 ℃　时间：2019-09-26 01:14:57

解答

O(0,0),A(-3,-4),B(5,-12),
OA^2=(0+3)^2+(0+4)^2=25,OA=5;
OB^2=(0-5)^2+(0+12)^2=169,OB=13;
OA*OB=5*13=65.