1 |
(2n-1)(2n+1) |
1 |
2 |
1 |
2n-1 |
1 |
2n+1 |
∴S=
1 |
1×3 |
1 |
3×5 |
1 |
(2n-1)(2n+1) |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
5 |
1 |
2n-1 |
1 |
2n+1 |
1 |
2 |
1 |
2n+1 |
∴S=
n |
2n+1 |
故答案为:
n |
2n+1 |
1 |
1×3 |
1 |
3×5 |
1 |
(2n-1)(2n+1) |
1 |
(2n-1)(2n+1) |
1 |
2 |
1 |
2n-1 |
1 |
2n+1 |
1 |
1×3 |
1 |
3×5 |
1 |
(2n-1)(2n+1) |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
5 |
1 |
2n-1 |
1 |
2n+1 |
1 |
2 |
1 |
2n+1 |
n |
2n+1 |
n |
2n+1 |