实数xy满足1≤y≤x,且2x²-5x+4=y(x-1),则x+y的值为
人气：128 ℃ 时间：2019-11-19 13:50:23
解答
1≤y=2x²-5x+4/(x-1)≤x,求解这个不等式,其中注意1≤x
可以发现(x-2)²≤0
x=2
当x=2时,带入2x²-5x+4=y(x-1),得出y=2
x+y=2+2=4
推荐
- 实数x、y满足x≥y≥1和2x^2-xy+5x-y+4=0,则x+y=___
- 实数X,Y满足X大于等于Y大于等于1和2X平方-xy-5x+y+4=o,则x+y的值
- 若正实数x、y满足2x＋y＋6＝xy,则xy最小值是?
- 若正实数x,y满足2x+y+6=xy,则xy的最小值是多少?
- 小弟跪求解析,实数x>1,y>=1.且2x^2-xy-5x+y+4=0.求x+y的值.
- 设二次方程anx²–an+1x+1=0有两个实数跟a和b,并且满足6a–2ab+6b=3.试用an表示an+1
- fill in the correct form in these sentences-has got,hasn't got,has he got,they've got,we haven't...
- 求解微分方程y''+y=cosx+1
猜你喜欢
