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求:怎样解出2t==[1+根号(1+4t^2)]/2可得t=0和t=2/3?
人气:253 ℃ 时间:2020-04-26 13:14:18
解答
2t = [ 1+ 根号(1+4t²)] / 2
4t = 1+ 根号(1+4t²)
4t -1 = 根号(1+4t²) l两边平方得
16t² - 8t + 1 = 1+4t²
12t² - 8t = 0
4t(3t - 2) = 0
∴ t =0 ,t= 2/3
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