a的平方+b的平方+4a-6b+13=0,求a的b次方的值
人气:211 ℃ 时间:2019-08-18 08:46:51
解答
a^2+b^2+4a-6b+4+9=0
(a^2+4a+4)+(b^2-6b+9)=0
(a+2)^2+(b-3)^2=0
平方大于等于0,相加等于0
若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
a=-2
b=3
a^b
=(-2)^3
=-8
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