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设f(x)为R上奇函数,且f(x+2)=-f(x),当0
人气:453 ℃ 时间:2020-03-19 12:39:53
解答
设f(x)为R上奇函数,且f(x+2)=-f(x),当0≤x≤1,f(x)=x,求f(7.5)由f(x+2)=-f(x)有f(7.5)=f(5.5+2) = -f(5.5) = -f(3.5+2) = -[-f(3.5)] = f(3.5) =f(1.5+2) = -f(1.5) = -f(-0.5+2) = f(-0.5)又因为f(x)为R上奇函数,所...
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