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已知f(x)的一个原函数为sinx/x 求x 乘f ` (x)的不定积分
人气:240 ℃ 时间:2020-06-03 01:12:31
解答
∫ f(x) dx = (sinx)/x
f(x) = d/dx (sinx)/x = (xcosx - sinx)/x²
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∫ xf'(x) dx
= ∫ x df(x)
= ∫ x df(x)
= xf(x) - ∫ f(x) dx
= x • (xcosx - sinx)/x² - (sinx)/x + C
= (xcosx - sinx)/x - (sinx)/x + C
= cosx - 2(sinx)/x + C
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