集合M={x|x=sin
,n∈Z},N={x|x=cos
,n∈Z},M∩N=( )
A. {-1,0,1}
B. {0,1}
C. {0}
D. ∅
人气:355 ℃ 时间:2020-04-02 20:41:31
解答
M={x|x=sin
,n∈Z}={
,0,−},
N={x|x=cos
,n∈Z}={0,-1,1},故M∩N={0},
故选C
推荐
- 若集合M={α |sinα≥1/2,0≤α≤π),N={α |cosα≤1/2,0≤α≤π},求M∩N.
- 已知集合M={α|sinα≥1/2,0<α<π},N={α|cosα≤1/2,0<α<π},求M∩N.
- 若集合M={θ|sinθ≥1/2,0≤θ≤π},N={θ|cosθ≤1/2,0≤θ≤π},求M∩N.
- sinθ=m-3/m+5,cosθ=4-2m/m+5,π/2〈θ〈π,求m的集合
- 设集合M={y|y=cos^2x-sin^2x|,x属于R},N={x
- he was ___ (too much,much too) worried about his son.请问此处填啥?
- 一元二次方程kx2-(2k-1)x+k+2=0,当k为何值时,方程有两个不相等的实数根?
猜你喜欢